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Find dydx\frac{dy}{dx}, if y=(5x23)4y=(-5x^{2}-3)^{-4}

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Q. Find dydx\frac{dy}{dx}, if y=(5x23)4y=(-5x^{2}-3)^{-4}
  1. Identify function: Identify the function to differentiate.\newlineWe are given the function y=(5x23)4y = (-5x^2 - 3)^{-4}. We need to find the derivative of this function with respect to xx.
  2. Apply chain rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is u4u^{-4} and the inner function is u=5x23u = -5x^2 - 3.
  3. Differentiate outer function: Differentiate the outer function with respect to the inner function uu. The derivative of u4u^{-4} with respect to uu is 4u5-4u^{-5}.
  4. Differentiate inner function: Differentiate the inner function uu with respect to xx. The derivative of u=5x23u = -5x^2 - 3 with respect to xx is dudx=10x\frac{du}{dx} = -10x.
  5. Apply chain rule: Apply the chain rule by multiplying the derivatives from Step 33 and Step 44. (dydx)=(4)(5x23)5×(10x)(\frac{dy}{dx}) = (-4)(-5x^2 - 3)^{-5} \times (-10x)
  6. Simplify expression: Simplify the expression. (dydx)=40x(5x23)5(\frac{dy}{dx}) = 40x(-5x^2 - 3)^{-5}

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