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Find dydx\frac{dy}{dx} for the given function.\newlinedy==x2csc(x)+5dy_=\square=x^{2}-\csc(x)+5

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Q. Find dydx\frac{dy}{dx} for the given function.\newlinedy==x2csc(x)+5dy_=\square=x^{2}-\csc(x)+5
  1. Identify Function: Identify the function to differentiate.\newlineWe are given the function y=x2csc(x)+5y = x^2 - \csc(x) + 5 and we need to find its derivative with respect to xx.
  2. Apply Sum Rule: Apply the sum rule for differentiation.\newlineThe sum rule states that the derivative of a sum of functions is the sum of their derivatives. Therefore, we can differentiate each term of yy separately.
  3. Differentiate x2x^2: Differentiate the first term, x2x^2, with respect to xx. Using the power rule, which states that the derivative of xnx^n with respect to xx is nx(n1)n\cdot x^{(n-1)}, we find that the derivative of x2x^2 is 2x(21)=2x2\cdot x^{(2-1)} = 2x.
  4. Differentiate csc(x)-\csc(x): Differentiate the second term, csc(x)-\csc(x), with respect to xx. The derivative of csc(x)\csc(x) is csc(x)cot(x)-\csc(x)\cot(x), so the derivative of csc(x)-\csc(x) is csc(x)cot(x)\csc(x)\cot(x).
  5. Differentiate 55: Differentiate the third term, 55, with respect to xx. The derivative of a constant is 00, so the derivative of 55 with respect to xx is 00.
  6. Combine Derivatives: Combine the derivatives of the individual terms.\newlineThe derivative of yy with respect to xx is the sum of the derivatives of the individual terms, which is 2x+csc(x)cot(x)+02x + \csc(x)\cot(x) + 0.
  7. Simplify Derivative: Simplify the derivative.\newlineSince the derivative of the constant term is 00, it does not contribute to the final expression. The simplified derivative of yy with respect to xx is dydx=2x+csc(x)cot(x)\frac{dy}{dx} = 2x + \csc(x)\cot(x).

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