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Find 
(d)/(dz)(3z^(3)+4sin z)
Answer:

Find ddz(3z3+4sinz) \frac{d}{d z}\left(3 z^{3}+4 \sin z\right) \newlineAnswer:

Full solution

Q. Find ddz(3z3+4sinz) \frac{d}{d z}\left(3 z^{3}+4 \sin z\right) \newlineAnswer:
  1. Apply Power Rule: To find the derivative of the function 3z3+4sin(z)3z^{3}+4\sin(z) with respect to zz, we need to apply the power rule for the polynomial term and the derivative rule for the trigonometric function.
  2. Apply Trig Derivative Rule: The power rule states that the derivative of znz^n with respect to zz is nz(n1)n*z^{(n-1)}. Applying this to the term 3z33z^{3}, we get 33z(31)=9z23*3*z^{(3-1)} = 9z^{2}.
  3. Combine Derivatives: The derivative of sin(z)\sin(z) with respect to zz is cos(z)\cos(z). Therefore, the derivative of 4sin(z)4\sin(z) with respect to zz is 4cos(z)4\cos(z).
  4. Combine Derivatives: The derivative of sin(z)\sin(z) with respect to zz is cos(z)\cos(z). Therefore, the derivative of 4sin(z)4\sin(z) with respect to zz is 4cos(z)4\cos(z).Combining the derivatives of both terms, we get the derivative of the entire function: ddz(3z3+4sin(z))=9z2+4cos(z)\frac{d}{dz}(3z^{3}+4\sin(z)) = 9z^{2} + 4\cos(z).

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