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Find 
(d)/(dx)(-cos(-3x-10))
Answer:

Find ddx(cos(3x10)) \frac{d}{d x}(-\cos (-3 x-10)) \newlineAnswer:

Full solution

Q. Find ddx(cos(3x10)) \frac{d}{d x}(-\cos (-3 x-10)) \newlineAnswer:
  1. Identify Functions: We need to find the derivative of the function cos(3x10)-\cos(-3x-10) with respect to xx. We will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Derivative of Outer Function: First, let's identify the outer function and the inner function. The outer function is cos(u)-\cos(u), and the inner function is u=3x10u = -3x - 10.
  3. Derivative of Inner Function: Now, we take the derivative of the outer function with respect to the inner function uu. The derivative of cos(u)-\cos(u) with respect to uu is sin(u)\sin(u), because the derivative of cos(u)\cos(u) is sin(u)-\sin(u) and we have an additional negative sign in front.
  4. Apply Chain Rule: Next, we take the derivative of the inner function u=3x10u = -3x - 10 with respect to xx. The derivative of 3x-3x with respect to xx is 3-3, and the derivative of a constant (10)(-10) is 00. So, the derivative of uu with respect to xx is 3-3.
  5. Substitute Inner Function: Now, we apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us sin(u)×(3)\sin(u) \times (-3).
  6. Simplify Final Answer: Substitute the inner function uu back into our expression to get the derivative in terms of xx. This gives us sin(3x10)×(3)\sin(-3x - 10) \times (-3).
  7. Simplify Final Answer: Substitute the inner function uu back into our expression to get the derivative in terms of xx. This gives us sin(3x10)×(3)\sin(-3x - 10) \times (-3).Finally, we simplify the expression to get the final answer. The derivative of cos(3x10)-\cos(-3x-10) with respect to xx is 3sin(3x10)-3\sin(-3x - 10).

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