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Find 
(d)/(dx)(4cos 2x)
Answer:

Find ddx(4cos2x) \frac{d}{d x}(4 \cos 2 x) \newlineAnswer:

Full solution

Q. Find ddx(4cos2x) \frac{d}{d x}(4 \cos 2 x) \newlineAnswer:
  1. Identify Functions: We are given the function f(x)=4cos(2x)f(x) = 4\cos(2x) and we need to find its derivative with respect to xx. We will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Derivative of Outer Function: First, let's identify the outer function and the inner function. The outer function is cos(u)\cos(u) where u=2xu = 2x, and the inner function is 2x2x. We will need to take the derivative of the outer function with respect to uu and then multiply it by the derivative of the inner function with respect to xx.
  3. Derivative of Inner Function: The derivative of the outer function cos(u)\cos(u) with respect to uu is sin(u)-\sin(u). So, the derivative of cos(2x)\cos(2x) with respect to 2x2x is sin(2x)-\sin(2x).
  4. Apply Chain Rule: The derivative of the inner function 2x2x with respect to xx is 22. This is because the derivative of xx with respect to xx is 11, and the constant multiple rule states that the derivative of a constant times a function is the constant times the derivative of the function.
  5. Simplify Expression: Now, we apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us the derivative of 4cos(2x)4\cos(2x) with respect to xx as 4×(sin(2x))×24 \times (-\sin(2x)) \times 2.
  6. Final Answer: Simplify the expression by multiplying the constants and keeping the function part as is. This results in 8sin(2x)-8\sin(2x).
  7. Final Answer: Simplify the expression by multiplying the constants and keeping the function part as is. This results in 8sin(2x)-8\sin(2x).We have found the derivative of 4cos(2x)4\cos(2x) with respect to xx, which is 8sin(2x)-8\sin(2x). This is our final answer.

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