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Find 
(d)/(dv)(5v^(3)+5sin v)
Answer:

Find ddv(5v3+5sinv) \frac{d}{d v}\left(5 v^{3}+5 \sin v\right) \newlineAnswer:

Full solution

Q. Find ddv(5v3+5sinv) \frac{d}{d v}\left(5 v^{3}+5 \sin v\right) \newlineAnswer:
  1. Identify Function: Identify the function to differentiate.\newlineWe are given the function f(v)=5v3+5sin(v)f(v) = 5v^{3} + 5\sin(v), and we need to find its derivative with respect to vv.
  2. Apply Sum Rule: Apply the sum rule for differentiation.\newlineThe sum rule states that the derivative of a sum of functions is the sum of their derivatives. Therefore, we can differentiate each term separately.
  3. Differentiate First Term: Differentiate the first term 5v35v^{3}. Using the power rule, which states that the derivative of vnv^n is nv(n1)n*v^{(n-1)}, we differentiate 5v35v^{3} to get 35v(31)=15v23*5v^{(3-1)} = 15v^{2}.
  4. Differentiate Second Term: Differentiate the second term 5sin(v)5\sin(v). The derivative of sin(v)\sin(v) with respect to vv is cos(v)\cos(v), so the derivative of 5sin(v)5\sin(v) is 5cos(v)5\cos(v).
  5. Combine Derivatives: Combine the derivatives of both terms.\newlineThe derivative of the function f(v)=5v3+5sin(v)f(v) = 5v^{3} + 5\sin(v) is the sum of the derivatives of its terms, which we found in steps 33 and 44. Therefore, the derivative is 15v2+5cos(v)15v^{2} + 5\cos(v).

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