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Find all solutions with -90^\circ < \theta < 90^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinetan(θ)=1\tan (\theta) = -1\newline____\_\_\_\_\,^\circ

Full solution

Q. Find all solutions with 90<θ<90-90^\circ < \theta < 90^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinetan(θ)=1\tan (\theta) = -1\newline____\_\_\_\_\,^\circ
  1. Identify Tangent Relationship: Since tan(θ)=sin(θ)cos(θ)\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}, we're looking for angles where the sine and cosine have the same absolute value but opposite signs.
  2. Determine Angle for Tangent=1-1: The tangent of an angle is 1-1 when the angle is 45°45° below the x-axis in the fourth quadrant or 45°45° above the x-axis in the second quadrant.
  3. Calculate Angle in Second Quadrant: In the second quadrant, the angle is 180°45°180° - 45°, which is 135°135°. But this is outside our range of -90° < \theta < 90°.
  4. Calculate Angle in Fourth Quadrant: In the fourth quadrant, the angle is 45-45^\circ, which is within our range.
  5. Final Solution: So the only solution within the given range is θ=45\theta = -45^\circ.

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