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Find all angles, 
0^(@) <= theta < 360^(@), that satisfy the equation below, to the nearest tenth of a degree.

-7sin^(2)theta-4sin theta+2=-1
Answer: 
theta=

Find all angles, 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline7sin2θ4sinθ+2=1 -7 \sin ^{2} \theta-4 \sin \theta+2=-1 \newlineAnswer: θ= \theta=

Full solution

Q. Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline7sin2θ4sinθ+2=1 -7 \sin ^{2} \theta-4 \sin \theta+2=-1 \newlineAnswer: θ= \theta=
  1. Simplify Equation: Simplify the given equation by adding 11 to both sides to set the equation to zero.\newline7sin2θ4sinθ+2=1-7\sin^{2}\theta - 4\sin \theta + 2 = -1\newline7sin2θ4sinθ+2+1=0-7\sin^{2}\theta - 4\sin \theta + 2 + 1 = 0\newline7sin2θ4sinθ+3=0-7\sin^{2}\theta - 4\sin \theta + 3 = 0
  2. Factor Quadratic Equation: Factor the quadratic equation in terms of sin(θ)\sin(\theta). We are looking for two numbers that multiply to 7×3=21-7 \times 3 = -21 and add up to 4-4. These numbers are 7-7 and +3+3. So, we can write the equation as: (7sin(θ)+3)(sin(θ)1)=0(-7\sin(\theta) + 3)(\sin(\theta) - 1) = 0
  3. Solve for sin(θ)\sin(\theta): Solve each factor set to zero for sin(θ)\sin(\theta).\newlineFirst factor: 7sin(θ)+3=0-7\sin(\theta) + 3 = 0\newline7sin(θ)=3-7\sin(\theta) = -3\newlinesin(θ)=37\sin(\theta) = \frac{3}{7}\newlineSecond factor: sin(θ)1=0\sin(\theta) - 1 = 0\newlinesin(θ)=1\sin(\theta) = 1
  4. Find Corresponding Angles: Find the angles that correspond to sin(θ)=37\sin(\theta) = \frac{3}{7} and sin(θ)=1\sin(\theta) = 1 within the range 0^\circ \leq \theta < 360^\circ. For sin(θ)=1\sin(\theta) = 1, the angle is 9090^\circ because sin(90)=1\sin(90^\circ) = 1. For sin(θ)=37\sin(\theta) = \frac{3}{7}, we need to use the inverse sine function or a calculator to find the angles. Using a calculator, we find: θ=arcsin(37)25.4\theta = \arcsin(\frac{3}{7}) \approx 25.4^\circ Since the sine function is positive in the first and second quadrants, we also need to find the angle in the second quadrant. θ=18025.4154.6\theta = 180^\circ - 25.4^\circ \approx 154.6^\circ
  5. Verify Solutions: Verify that the angles found are within the given range and list all the solutions.\newlineThe angles 9090^\circ, 25.425.4^\circ, and 154.6154.6^\circ are all within the range 0^\circ \leq \theta < 360^\circ.\newlineTherefore, the solutions are θ25.4\theta \approx 25.4^\circ, 9090^\circ, and 154.6154.6^\circ.

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