Q. Find all angles, 0∘≤θ<360∘, that satisfy the equation below, to the nearest tenth of a degree.9tan2θ+19tanθ=−2Answer: θ=
Rewrite Equation in Quadratic Form: Rewrite the given equation in a quadratic form by moving all terms to one side.9tan2(θ)+19tan(θ)+2=0
Factor Quadratic Equation: Factor the quadratic equation to find the values of tan(θ).(3tan(θ)+1)(3tan(θ)+2)=0
Solve for tan(θ): Set each factor equal to zero and solve for tan(θ).First factor: 3tan(θ)+1=0tan(θ)=−31
Find Corresponding Angles: Find the angles that correspond to the tangent values found in Step 3 within the range 0^\circ \leq \theta < 360^\circ. For tan(θ)=−31, use an inverse tangent function or a calculator to find the reference angle. θ=arctan(−31)≈−18.4∘ Since the tangent function is negative in the second and fourth quadrants, add 180∘ to find the angle in the second quadrant and use the reference angle to find the angle in the fourth quadrant. Second quadrant: 180∘−18.4∘≈161.6∘ Fourth quadrant: 360∘−18.4∘≈341.6∘
List All Angles: List all the angles found in Step 4 that are within the range 0^\circ \leq \theta < 360^\circ.θ≈161.6∘,341.6∘,146.3∘,326.3∘
More problems from Csc, sec, and cot of special angles