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Find a2a_2 and a3a_3.\newline\newlinea1=2a_1 = 2\newlinean=2an−1a_n = 2a_{n - 1}\newline\newlineWrite your answers as integers or fractions in simplest form.\newline\newlinea2=a_2 = ______\newlinea3=a_3 = ______

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Q. Find a2a_2 and a3a_3.\newline\newlinea1=2a_1 = 2\newlinean=2an−1a_n = 2a_{n - 1}\newline\newlineWrite your answers as integers or fractions in simplest form.\newline\newlinea2=a_2 = ______\newlinea3=a_3 = ______
  1. Find a2a_2: To find a2a_2, we use the formula an=2×a(n−1)a_n = 2 \times a_{(n - 1)} with n=2n = 2.\newlineSo, a2=2×a1a_2 = 2 \times a_1.\newlinea2=2×2a_2 = 2 \times 2.\newlinea2=4a_2 = 4.
  2. Find a3a_3: Now, to find a3a_3, we again use the formula an=2×an−1a_n = 2 \times a_{n - 1} with n=3n = 3.\newlineSo, a3=2×a2a_3 = 2 \times a_2.\newlinea3=2×4a_3 = 2 \times 4.\newlinea3=8a_3 = 8.

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