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Factorise:\newline(3x4y)4x4(3x - 4y)^4 - x^4

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Q. Factorise:\newline(3x4y)4x4(3x - 4y)^4 - x^4
  1. Recognize as difference of squares: Recognize the expression as a difference of two squares. The given expression is a difference of two squares because it can be written as A4B4A^4 - B^4, where A=(3x4y)A = (3x - 4y) and B=xB = x.
  2. Apply formula: Apply the difference of squares formula.\newlineThe difference of squares formula is A2B2=(AB)(A+B)A^2 - B^2 = (A - B)(A + B). In this case, we can apply the formula to A2A^2 and B2B^2, where A2=(3x4y)2A^2 = (3x - 4y)^2 and B2=x2B^2 = x^2.
  3. Write as difference of squares: Write the expression as a difference of squares.\newlineUsing the formula from Step 22, we can write the expression as:\newline((3x4y)2)2(x2)2=((3x4y)2x2)((3x4y)2+x2)((3x - 4y)^2)^2 - (x^2)^2 = ((3x - 4y)^2 - x^2)((3x - 4y)^2 + x^2)
  4. Expand terms: Expand the terms inside the parentheses.\newlineWe need to expand (3x4y)2(3x - 4y)^2 and x2x^2:\newline(3x4y)2=9x224xy+16y2(3x - 4y)^2 = 9x^2 - 24xy + 16y^2 (by squaring each term and applying the distributive property)\newlinex2=x2x^2 = x^2 (no expansion needed)
  5. Substitute expanded terms: Substitute the expanded terms back into the factored form.\newlineSubstitute the expanded form of (3x4y)2(3x - 4y)^2 into the factored expression from Step 33:\newline(9x224xy+16y2x2)(9x224xy+16y2+x2)(9x^2 - 24xy + 16y^2 - x^2)(9x^2 - 24xy + 16y^2 + x^2)
  6. Combine like terms: Combine like terms in each factor.\newlineIn the first factor, combine 9x29x^2 and x2-x^2 to get 8x28x^2. In the second factor, combine 9x29x^2 and x2x^2 to get 10x210x^2:\newline(8x224xy+16y2)(10x224xy+16y2)(8x^2 - 24xy + 16y^2)(10x^2 - 24xy + 16y^2)
  7. Check for further factorization: Check for any further factorization. The terms within each factor do not have a common factor, and the expression cannot be factored further.

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