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Factor.\newlinev22v+1v^2 - 2v + 1

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Q. Factor.\newlinev22v+1v^2 - 2v + 1
  1. Determine Approach: Determine the approach to factor v22v+1v^2 - 2v + 1. This expression is a perfect square trinomial because it can be written in the form (ab)2(a - b)^2 where a2=v2a^2 = v^2, 2ab=2v2ab = 2v, and b2=1b^2 = 1.
  2. Identify Values: Identify the values of aa and bb that satisfy the equation (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2. For the given expression, a=va = v and b=1b = 1 because v2=(v)2v^2 = (v)^2 and 1=(1)21 = (1)^2.
  3. Write Factored Form: Write the factored form using the values of aa and bb. The factored form is (v1)(v1)(v - 1)(v - 1) or (v1)2(v - 1)^2.