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Factor the trinomial:

5x^(2)+37 x+42
Answer:

Factor the trinomial:\newline5x2+37x+42 5 x^{2}+37 x+42 \newlineAnswer:

Full solution

Q. Factor the trinomial:\newline5x2+37x+42 5 x^{2}+37 x+42 \newlineAnswer:
  1. Identify structure and numbers: Identify the structure of the trinomial and look for two numbers that multiply to give the product of the coefficient of x2x^2 term (55) and the constant term (4242), which is 5×42=2105\times42=210, and add up to the coefficient of the xx term (3737).
  2. Find numbers satisfying conditions: Find two numbers that multiply to 210210 and add up to 3737. After testing different combinations, we find that 1414 and 1515 are the numbers that satisfy both conditions because 14×15=21014 \times 15 = 210 and 14+15=3714 + 15 = 37.
  3. Rewrite middle term: Rewrite the middle term 37x37x using the two numbers found in Step 22. This gives us 5x2+14x+15x+425x^2 + 14x + 15x + 42.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms: (5x2+14x)+(15x+42)(5x^2 + 14x) + (15x + 42).
  5. Factor out common factors: Factor out the greatest common factor from each group. From the first group, we can factor out xx, and from the second group, we can factor out 33. This gives us x(5x+14)+3(5x+14)x(5x + 14) + 3(5x + 14).
  6. Final answer: Since both groups contain the common factor (5x+14)(5x + 14), factor this out to get the final answer: (x+3)(5x+14)(x + 3)(5x + 14).

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