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Factor the trinomial:

2x^(2)+17 x+30
Answer:

Factor the trinomial:\newline2x2+17x+30 2 x^{2}+17 x+30 \newlineAnswer:

Full solution

Q. Factor the trinomial:\newline2x2+17x+30 2 x^{2}+17 x+30 \newlineAnswer:
  1. Identify trinomial: Identify the trinomial that needs to be factored.\newlineThe trinomial given is 2x2+17x+302x^2 + 17x + 30.
  2. Find two numbers: Look for two numbers that multiply to give the product of the coefficient of x2x^2 term (which is 22) and the constant term (which is 3030), and add up to the coefficient of the xx term (which is 1717).\newlineWe need two numbers that multiply to 2×30=602 \times 30 = 60 and add up to 1717.
  3. Find pair of numbers: Find the pair of numbers that meet the criteria from Step 22.\newlineThe numbers 55 and 1212 multiply to 6060 (5×12=605 \times 12 = 60) and add up to 1717 (5+12=175 + 12 = 17).
  4. Write middle term: Write the middle term 17x17x as the sum of two terms using the numbers found in Step 33.\newline17x17x can be written as 5x+12x5x + 12x.\newlineSo, the trinomial 2x2+17x+302x^2 + 17x + 30 can be rewritten as 2x2+5x+12x+302x^2 + 5x + 12x + 30.
  5. Factor by grouping: Factor by grouping.\newlineGroup the terms into two pairs: (2x2+5x)(2x^2 + 5x) and (12x+30)(12x + 30).
  6. Factor out common factor: Factor out the greatest common factor from each group.\newlineFrom the first group 2x2+5x2x^2 + 5x, we can factor out an xx to get x(2x+5)x(2x + 5).\newlineFrom the second group 12x+3012x + 30, we can factor out a 66 to get 6(2x+5)6(2x + 5).
  7. Write final factored form: Write the final factored form using the common binomial factor from both groups.\newlineSince both groups contain the binomial (2x+5)(2x + 5), the trinomial can be factored as (x+6)(2x+5)(x + 6)(2x + 5).

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