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Factor completely:

z^(9)+1
Answer:

Factor completely:\newlinez9+1 z^{9}+1 \newlineAnswer:

Full solution

Q. Factor completely:\newlinez9+1 z^{9}+1 \newlineAnswer:
  1. Recognize Sum of Cubes: Step Title: Recognize the Sum of Two Cubes\newlineConcise Step Description: Identify that the expression is a sum of two cubes, which can be factored using the formula a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2).\newlineStep Calculation: In this case, z9z^9 is (z3)3(z^3)^3 and 11 is 131^3, so we can apply the sum of cubes formula.\newlineStep Output: Recognize that z9+1z^9 + 1 is a sum of two cubes.
  2. Apply Sum of Cubes Formula: Step Title: Apply the Sum of Two Cubes Formula\newlineConcise Step Description: Apply the sum of cubes formula to factor the expression.\newlineStep Calculation: Using the formula, we get (z3+1)((z3)2z31+12)(z^3 + 1)((z^3)^2 - z^3\cdot 1 + 1^2).\newlineStep Output: Factored form is (z3+1)(z6z3+1)(z^3 + 1)(z^6 - z^3 + 1).
  3. Check Further Factorization: Step Title: Check for Further Factorization\newlineConcise Step Description: Check if the factors obtained can be factored further.\newlineStep Calculation: The first factor z3+1z^3 + 1 is a sum of cubes again and can be factored further. The second factor z6z3+1z^6 - z^3 + 1 is not factorable over the real numbers.\newlineStep Output: Further factor the first term (z3+1)(z^3 + 1) using the sum of cubes formula.
  4. Factor First Term Further: Step Title: Factor the First Term Further\newlineConcise Step Description: Factor the first term z3+1z^3 + 1 using the sum of cubes formula.\newlineStep Calculation: We have z3+13z^3 + 1^3, which factors to (z+1)(z2z1+12)(z + 1)(z^2 - z\cdot 1 + 1^2).\newlineStep Output: Factored form is (z+1)(z2z+1)(z + 1)(z^2 - z + 1).
  5. Combine Factored Terms: Step Title: Combine the Factored Terms\newlineConcise Step Description: Combine the factored terms to get the completely factored expression.\newlineStep Calculation: The completely factored expression is (z+1)(z2z+1)(z6z3+1)(z + 1)(z^2 - z + 1)(z^6 - z^3 + 1).\newlineStep Output: The final factored form is (z+1)(z2z+1)(z6z3+1)(z + 1)(z^2 - z + 1)(z^6 - z^3 + 1).