Factor completely. y^(2)-4x^(6) Answer:

Recognize as difference of squares: Recognize the expression y^2 - 4x^6 as a difference of squares. A difference of squares is a binomial of the form a^2 - b^2, which factors into (a + b)(a - b). Here, y^2 is a perfect square (a^2) and 4x^6 is also a perfect square (b^2) since 4x^6 = (2x^3)^2.Write expression as difference: Write the expression as a difference of squares. y^2 - 4x^6 = y^2 - (2x^3)^2 Now we can apply the difference of squares formula.Factor using formula: Factor the expression using the difference of squares formula. y^2 - (2x^3)^2 = (y + 2x^3)(y - 2x^3) This is the completely factored form of the expression.

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Factor completely.

y^(2)-4x^(6)
Answer:

Factor completely. $\newline$ $y^{2}-4 x^{6}$ $\newline$ Answer:

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Algebra 2

Multiply and divide rational expressions

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Q. Factor completely.

\newline

y^{2}-4 x^{6}

\newline

Answer:

Recognize as difference of squares: Recognize the expression $y^2 - 4x^6$ as a difference of squares. $\newline$ A difference of squares is a binomial of the form $a^2 - b^2$ , which factors into $(a + b)(a - b)$ . $\newline$ Here, $y^2$ is a perfect square $(a^2)$ and $4x^6$ is also a perfect square $(b^2)$ since $4x^6 = (2x^3)^2$ .
Write expression as difference: Write the expression as a difference of squares. $\newline$ $y^2 - 4x^6 = y^2 - (2x^3)^2$ $\newline$ Now we can apply the difference of squares formula.
Factor using formula: Factor the expression using the difference of squares formula. $\newline$ $y^2 - (2x^3)^2 = (y + 2x^3)(y - 2x^3)$ $\newline$ This is the completely factored form of the expression.