Factor completely: (x-8)^(5)+(x-8)^(6) Answer:

Identify Common Factor: Identify the common factor in both terms. Both terms have a common factor of (x-8) raised to the power of 5.Factor Out Common Factor: Factor out the common factor from both terms. We can factor out (x-8)^(5) from both terms to get (x-8)^(5) * [1 + (x-8)].Simplify Inside Brackets: Simplify the expression inside the brackets. Simplify the expression inside the brackets to get (x-8)^(5) * (x-8+1).Combine Like Terms: Combine like terms inside the brackets. Combine -8 and +1 to get -7, so the expression becomes (x-8)^(5) * (x-7).Write Final Form: Write the final factored form. The completely factored form of the expression is (x-8)^(5) * (x-7).

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Factor completely:

(x-8)^(5)+(x-8)^(6)
Answer:

Factor completely: $\newline$ $(x-8)^{5}+(x-8)^{6}$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

(x-8)^{5}+(x-8)^{6}

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms. $\newline$ Both terms have a common factor of $(x-8)^5$ .
Factor Out Common Factor: Factor out the common factor from both terms. $\newline$ We can factor out $(x-8)^{5}$ from both terms to get $(x-8)^{5} \times [1 + (x-8)]$ .
Simplify Inside Brackets: Simplify the expression inside the brackets. $\newline$ Simplify the expression inside the brackets to get $(x-8)^{5} \times (x-8+1)$ .
Combine Like Terms: Combine like terms inside the brackets. $\newline$ Combine $-8$ and $+1$ to get $-7$ , so the expression becomes $(x-8)^{5} \cdot (x-7)$ .
Write Final Form: Write the final factored form. $\newline$ The completely factored form of the expression is $(x-8)^{5} \times (x-7)$ .