Factor completely. x^(6)y^(4)-1 Answer:

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Factor completely.  x^(6)y^(4)-1 Answer:

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Recognize Difference of Squares: Step Title: Recognize the Difference of Squares Concise Step Description: Identify that the expression is a difference of two squares. Step Calculation: Recognize that $x^{6}y^{4}$ is a square ($x^{3}y^{2}$)^2 and 1 is also a square (1^2). Step Output: The expression can be written as ($x^{3}y^{2}$)^2 - 1^2.Apply Squares Formula: Step Title: Apply the Difference of Squares Formula Concise Step Description: Use the formula $a^2 - b^2 = (a + b)(a - b)$ to factor the expression. Step Calculation: Apply the formula with $a = x^{3}y^{2}$ and $b = 1$. Step Output: The factored form is ($x^{3}y^{2} + 1$)($x^{3}y^{2} - 1$).Factor Further if Possible: Step Title: Factor Further if Possible Concise Step Description: Check if the resulting terms can be factored further. Step Calculation: The term $x^{3}y^{2} + 1$ cannot be factored further as it is not a difference of squares. The term $x^{3}y^{2} - 1$ is a difference of squares and can be factored further. Step Output: We need to factor $x^{3}y^{2} - 1$ further.Factor Second Difference of Squares: Step Title: Factor the Second Difference of Squares Concise Step Description: Factor $x^{3}y^{2} - 1$ using the difference of squares formula again. Step Calculation: Recognize that $x^{3}y^{2}$ is a square ($xy$)^6 and 1 is a square (1^2). Apply the formula with $a = xy$ and $b = 1$. Step Output: The factored form is ($xy + 1$)($xy - 1$).

Factor completely. $\newline$ $x^{6} y^{4}-1$ $\newline$ Answer:

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Factor completely. $\newline$ $x^{6} y^{4}-1$ $\newline$ Answer: