Factor completely: x^(2)(x^(2)+3)-x(x^(2)+3)-2(x^(2)+3) Answer:

Identify common factor: Identify the common factor in all terms. The common factor in all terms is (x^(2) + 3).Factor out common factor: Factor out the common factor from each term. The expression can be rewritten as (x^(2) + 3)(x^(2) - x - 2).Factor quadratic expression: Factor the quadratic expression. We need to factor the quadratic x^(2) - x - 2. To do this, we look for two numbers that multiply to -2 and add up to -1. These numbers are -2 and 1.Write factored form: Write the factored form of the quadratic. The quadratic x^(2) - x - 2 can be factored as (x - 2)(x + 1).Combine with common factor: Combine the factored quadratic with the common factor. The completely factored form of the original expression is (x^(2) + 3)(x - 2)(x + 1).

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Factor completely:

x^(2)(x^(2)+3)-x(x^(2)+3)-2(x^(2)+3)
Answer:

Factor completely: $\newline$ $x^{2}\left(x^{2}+3\right)-x\left(x^{2}+3\right)-2\left(x^{2}+3\right)$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

x^{2}\left(x^{2}+3\right)-x\left(x^{2}+3\right)-2\left(x^{2}+3\right)

\newline

Answer:

Identify common factor: Identify the common factor in all terms. $\newline$ The common factor in all terms is $(x^{2} + 3)$ .
Factor out common factor: Factor out the common factor from each term. $\newline$ The expression can be rewritten as $x^{2} + 3)\$x^{2} - x - 2$ .
Factor quadratic expression: Factor the quadratic expression. $\newline$ We need to factor the quadratic $x^{2} - x - 2$ . To do this, we look for two numbers that multiply to $-2$ and add up to $-1$ . These numbers are $-2$ and $1$ .
Write factored form: Write the factored form of the quadratic. $\newline$ The quadratic $x^{2} - x - 2$ can be factored as $(x - 2)(x + 1)$ .
Combine with common factor: Combine the factored quadratic with the common factor. $\newline$ The completely factored form of the original expression is $(x^{2} + 3)(x - 2)(x + 1)$ .