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Factor completely:

w^(6)-1
Answer:

Factor completely:\newlinew61 w^{6}-1 \newlineAnswer:

Full solution

Q. Factor completely:\newlinew61 w^{6}-1 \newlineAnswer:
  1. Recognize Difference of Squares: Step Title: Recognize the Difference of Squares\newlineConcise Step Description: Identify that the expression is a difference of squares, which can be factored into the product of a sum and difference.\newlineStep Calculation: Recognize that w61w^6 - 1 is a difference of squares because it can be written as (w3)212(w^3)^2 - 1^2.\newlineStep Output: Difference of squares: (w3)212(w^3)^2 - 1^2
  2. Apply Squares Formula: Step Title: Apply the Difference of Squares Formula\newlineConcise Step Description: Use the difference of squares formula, which states that a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b), to factor the expression.\newlineStep Calculation: Apply the formula with a=w3a = w^3 and b=1b = 1 to get (w3+1)(w31)(w^3 + 1)(w^3 - 1).\newlineStep Output: Factored form: (w3+1)(w31)(w^3 + 1)(w^3 - 1)
  3. Factor Further if Possible: Step Title: Factor Further if Possible\newlineConcise Step Description: Check if the resulting binomials can be factored further, especially the w31w^3 - 1 term, which is also a difference of cubes.\newlineStep Calculation: Recognize that w31w^3 - 1 is a difference of cubes and can be factored using the formula a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2) with a=wa = w and b=1b = 1.\newlineStep Output: Factored form of w31w^3 - 1: (w1)(w2+w+1)(w - 1)(w^2 + w + 1)
  4. Combine Factored Forms: Step Title: Combine Factored Forms\newlineConcise Step Description: Combine the factored forms from the previous steps to write the completely factored expression.\newlineStep Calculation: The completely factored form is (w3+1)(w1)(w2+w+1)(w^3 + 1)(w - 1)(w^2 + w + 1).\newlineStep Output: Completely factored form: (w3+1)(w1)(w2+w+1)(w^3 + 1)(w - 1)(w^2 + w + 1)