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Factor completely.

9x^(6)-1
Answer:

Factor completely.\newline9x61 9 x^{6}-1 \newlineAnswer:

Full solution

Q. Factor completely.\newline9x61 9 x^{6}-1 \newlineAnswer:
  1. Recognize Difference of Squares: Step Title: Recognize the Difference of Squares\newlineConcise Step Description: Identify that the expression is a difference of squares, which can be factored into the product of a sum and difference.\newlineStep Calculation: Recognize that 9x69x^6 is a perfect square, as is 11, so the expression 9x619x^6 - 1 can be written as (3x3)212(3x^3)^2 - 1^2.
  2. Apply Squares Formula: Step Title: Apply the Difference of Squares Formula\newlineConcise Step Description: Use the difference of squares formula a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b) to factor the expression.\newlineStep Calculation: Apply the formula with a=3x3a = 3x^3 and b=1b = 1 to get (3x3+1)(3x31)(3x^3 + 1)(3x^3 - 1).
  3. Factor Further if Possible: Step Title: Factor Further if Possible\newlineConcise Step Description: Check if the resulting binomials can be factored further.\newlineStep Calculation: Notice that 3x3+13x^3 + 1 cannot be factored further over the integers, but 3x313x^3 - 1 is again a difference of squares, as it can be written as (33x)313(\sqrt[3]{3}x)^3 - 1^3.
  4. Apply Cubes Formula: Step Title: Apply the Difference of Cubes Formula\newlineConcise Step Description: Use the difference of cubes formula a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2) to factor 3x313x^3 - 1.\newlineStep Calculation: Apply the formula with a=33xa = \sqrt[3]{3}x and b=1b = 1 to get (33x1)((33x)2+(33x)(1)+12)(\sqrt[3]{3}x - 1)((\sqrt[3]{3}x)^2 + (\sqrt[3]{3}x)(1) + 1^2).
  5. Simplify Resulting Expression: Step Title: Simplify the Resulting Expression\newlineConcise Step Description: Simplify the expression obtained from the difference of cubes formula.\newlineStep Calculation: The simplified form is (33x1)(3x2+33x+1)(\sqrt[3]{3}x - 1)(3x^2 + \sqrt[3]{3}x + 1).
  6. Combine All Factors: Step Title: Combine All Factors\newlineConcise Step Description: Combine all factors obtained from the previous steps to write the completely factored form of the original expression.\newlineStep Calculation: The completely factored form is (3x3+1)(33x1)(3x2+33x+1)(3x^3 + 1)(\sqrt[3]{3}x - 1)(3x^2 + \sqrt[3]{3}x + 1).