Factor completely: (8x-7)^(2)-(2x+1)^(2) Answer:

Recognize as difference of squares: Recognize the expression as a difference of squares. The given expression is in the form of a^2 - b^2, which can be factored into (a + b)(a - b).Identify 'a' and 'b': Identify 'a' and 'b' in the expression. In the expression (8x-7)^(2)-(2x+1)^(2), 'a' is (8x-7) and 'b' is (2x+1).Apply formula: Apply the difference of squares formula. Using the formula (a^2 - b^2) = (a + b)(a - b), we get: ((8x-7) + (2x+1))((8x-7) - (2x+1))Simplify expressions: Simplify the expressions inside the parentheses. Simplify (8x-7) + (2x+1) to get 10x - 6. Simplify (8x-7) - (2x+1) to get 6x - 8.Write final factored form: Write the final factored form. The factored form of the expression is (10x - 6)(6x - 8).

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Factor completely:

(8x-7)^(2)-(2x+1)^(2)
Answer:

Factor completely: $\newline$ $(8 x-7)^{2}-(2 x+1)^{2}$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

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Q. Factor completely:

\newline

(8 x-7)^{2}-(2 x+1)^{2}

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Answer:

Recognize as difference of squares: Recognize the expression as a difference of squares. The given expression is in the form of $a^2 - b^2$ , which can be factored into $(a + b)(a - b)$ .
Identify 'a' and 'b': Identify 'a' and 'b' in the expression. $\newline$ In the expression $(8x-7)^{2}-(2x+1)^{2}$ , 'a' is $(8x-7)$ and 'b' is $(2x+1)$ .
Apply formula: Apply the difference of squares formula. $\newline$ Using the formula $(a^2 - b^2) = (a + b)(a - b)$ , we get: $\newline$ $((8x-7) + (2x+1))((8x-7) - (2x+1))$
Simplify expressions: Simplify the expressions inside the parentheses. $\newline$ Simplify $(8x-7) + (2x+1)$ to get $10x - 6$ . $\newline$ Simplify $(8x-7) - (2x+1)$ to get $6x - 8$ .
Write final factored form: Write the final factored form. $\newline$ The factored form of the expression is $(10x - 6)(6x - 8)$ .