Factor completely: 5x(4x+3)+2(4x+3) Answer:

Identify Common Factor: Identify the common factor in both terms. Both terms 5x(4x+3) and 2(4x+3) have a common factor of (4x+3).Factor Out Common Factor: Factor out the common factor (4x+3). The expression can be written as (4x+3)(5x+2) by factoring out the common factor.Check Factored Expression: Check the factored expression by distributing to ensure it matches the original expression. (4x+3)(5x) + (4x+3)(2) should result in the original expression 5x(4x+3)+2(4x+3). Distributing gives us 20x^2 + 15x + 8x + 6, which simplifies to 20x^2 + 23x + 6. This does not match the original expression, indicating a math error in the distribution.

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Factor completely:

5x(4x+3)+2(4x+3)
Answer:

Factor completely: $\newline$ $5 x(4 x+3)+2(4 x+3)$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

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Q. Factor completely:

\newline

5 x(4 x+3)+2(4 x+3)

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms. $\newline$ Both terms $5x(4x+3)$ and $2(4x+3)$ have a common factor of $(4x+3)$ .
Factor Out Common Factor: Factor out the common factor $(4x+3)$ . The expression can be written as $(4x+3)(5x+2)$ by factoring out the common factor.
Check Factored Expression: Check the factored expression by distributing to ensure it matches the original expression. $\newline$ $(4x+3)(5x) + (4x+3)(2)$ should result in the original expression $5x(4x+3)+2(4x+3)$ . $\newline$ Distributing gives us $20x^2 + 15x + 8x + 6$ , which simplifies to $20x^2 + 23x + 6$ . $\newline$ This does not match the original expression, indicating a math error in the distribution.