Factor completely. -5x^(3)-80x^(2)-140 x Answer:

Identify Common Factor: Look for a common factor in all three terms. -5x^3, -80x^2, and -140x all have a common factor of -5x.Factor Out Common Factor: Factor out the common factor of -5x. -5x^3 - 80x^2 - 140x = -5x(x^2 + 16x + 28)Find Quadratic Factors: Look for factors of the quadratic x^2 + 16x + 28. We need two numbers that multiply to 28 and add up to 16. These numbers are 4 and 7.Factor the Quadratic: Factor the quadratic. x^2 + 16x + 28 can be factored as (x + 4)(x + 7).Write Completely Factored Form: Write the completely factored form of the original polynomial. -5x^3 - 80x^2 - 140x = -5x(x + 4)(x + 7)

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Factor completely.

-5x^(3)-80x^(2)-140 x
Answer:

Factor completely. $\newline$ $-5 x^{3}-80 x^{2}-140 x$ $\newline$ Answer:

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Algebra 2

Evaluate rational exponents

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Q. Factor completely.

\newline

-5 x^{3}-80 x^{2}-140 x

\newline

Answer:

Identify Common Factor: Look for a common factor in all three terms. $\newline$ $-5x^3$ , $-80x^2$ , and $-140x$ all have a common factor of $-5x$ .
Factor Out Common Factor: Factor out the common factor of $-5x$ . $-5x^3 - 80x^2 - 140x = -5x(x^2 + 16x + 28)$
Find Quadratic Factors: Look for factors of the quadratic $x^2 + 16x + 28$ . We need two numbers that multiply to $28$ and add up to $16$ . These numbers are $4$ and $7$ .
Factor the Quadratic: Factor the quadratic. $x^2 + 16x + 28$ can be factored as $(x + 4)(x + 7)$ .
Write Completely Factored Form: Write the completely factored form of the original polynomial. $\newline$ $-5x^3 - 80x^2 - 140x = -5x(x + 4)(x + 7)$