Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor completely.

5x^(2)+14 x-3
Answer:

Factor completely.\newline5x2+14x3 5 x^{2}+14 x-3 \newlineAnswer:

Full solution

Q. Factor completely.\newline5x2+14x3 5 x^{2}+14 x-3 \newlineAnswer:
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is 5x2+14x35x^2 + 14x - 3. Here, the coefficient of x2x^2 (a)(a) is 55, the coefficient of xx (b)(b) is 1414, and the constant term (c)(c) is 3-3.
  2. Find Multiplying Numbers: Look for two numbers that multiply to acac (aa times cc) and add up to bb. We need to find two numbers that multiply to (5)(3)=15(5)(-3) = -15 and add up to 1414. The numbers that satisfy these conditions are 1515 and 1-1 because 15×1=1515 \times -1 = -15 and 15+(1)=1415 + (-1) = 14.
  3. Rewrite Middle Term: Rewrite the middle term using the two numbers found in Step 22.\newlineWe can express 14x14x as 15xx15x - x. So, the expression becomes 5x2+15xx35x^2 + 15x - x - 3.
  4. Factor by Grouping: Factor by grouping.\newlineWe group the terms as follows: (5x2+15x)(x+3)(5x^2 + 15x) - (x + 3). Now we factor out the common factors from each group. From the first group, we can factor out 5x5x, and from the second group, we can factor out 1-1.\newlineThis gives us: 5x(x+3)1(x+3)5x(x + 3) - 1(x + 3).
  5. Factor Common Binomial: Factor out the common binomial factor.\newlineWe can now see that (x+3)(x + 3) is a common factor in both terms. Factoring this out gives us: (x+3)(5x1)(x + 3)(5x - 1).