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Factor completely.

5x^(2)+12 x+7
Answer:

Factor completely.\newline5x2+12x+7 5 x^{2}+12 x+7 \newlineAnswer:

Full solution

Q. Factor completely.\newline5x2+12x+7 5 x^{2}+12 x+7 \newlineAnswer:
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is 5x2+12x+75x^2 + 12x + 7.\newlineHere, a=5a = 5, b=12b = 12, and c=7c = 7.
  2. Find Multiplying Numbers: Find two numbers that multiply to aca*c (57=355*7 = 35) and add up to bb (1212).\newlineWe need to find two numbers that multiply to 3535 and add up to 1212.\newlineThe numbers 55 and 77 satisfy these conditions because 57=355*7 = 35 and 5+7=125+7 = 12.
  3. Write Middle Term: Write the middle term 12x12x as the sum of two terms using the numbers found in the previous step.\newlineWe can express 12x12x as 5x+7x5x + 7x.\newlineSo, the expression becomes 5x2+5x+7x+75x^2 + 5x + 7x + 7.
  4. Factor by Grouping: Factor by grouping.\newlineGroup the terms as follows: (5x2+5x)+(7x+7)(5x^2 + 5x) + (7x + 7).\newlineFactor out the common factors from each group.\newlineFrom the first group, we can factor out 5x5x, and from the second group, we can factor out 77.\newlineThis gives us 5x(x+1)+7(x+1)5x(x + 1) + 7(x + 1).
  5. Factor Common Binomial: Factor out the common binomial factor.\newlineBoth groups contain the common factor (x+1)(x + 1).\newlineFactor this out to get the final factored form: (5x+7)(x+1)(5x + 7)(x + 1).