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Factor completely.

50-8x^(10)
Answer:

Factor completely.\newline508x10 50-8 x^{10} \newlineAnswer:

Full solution

Q. Factor completely.\newline508x10 50-8 x^{10} \newlineAnswer:
  1. Identify GCF: Identify the greatest common factor (GCF) of the terms in the expression 508x1050 - 8x^{10}. The GCF of 5050 and 88 is 22. However, since 88 is a multiple of 22 and we have an xx term with a power of 1010, we should look for the GCF that includes the variable as well. The GCF that includes the variable is 2x102x^{10} since x10x^{10} is the highest power of xx present, but we cannot use x10x^{10} as a factor because it is not a factor of the constant term 5050. Therefore, the correct GCF is just 22.
  2. Factor out GCF: Factor out the GCF from the expression. \newline2(254x10)2(25 - 4x^{10})\newlineCheck to ensure that when we distribute the 22 back into the parentheses, we get the original expression.\newline2×25=502 \times 25 = 50\newline2×(4x10)=8x102 \times (-4x^{10}) = -8x^{10}\newlineThe original expression is correctly factored.
  3. Check for Further Factoring: Check if the expression inside the parentheses can be factored further.\newlineThe expression 254x1025 - 4x^{10} is a difference of squares because it can be written as (52)(2x5)2(5^2) - (2x^5)^2.\newlineWe can factor a difference of squares using the identity a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b).
  4. Apply Difference of Squares: Apply the difference of squares identity to factor the expression inside the parentheses.\newline(5+2x5)(52x5)(5 + 2x^5)(5 - 2x^5)\newlineEnsure that when we square the terms 55 and 2x52x^5, we get the original terms inside the parentheses.\newline(5)2=25(5)^2 = 25\newline(2x5)2=4x10(2x^5)^2 = 4x^{10}\newlineThe factoring is correct.
  5. Combine GCF with Factored Form: Combine the GCF with the factored form of the expression inside the parentheses to get the final factored form. \newline2(5+2x5)(52x5)2(5 + 2x^5)(5 - 2x^5)\newlineCheck one last time to ensure that when we distribute the 22 into the factored form and then multiply the binomials, we get the original expression.