Factor completely: 5(x+4)^(2)+(x+4)^(3) Answer:

Identify Common Factor: Identify the common factor in both terms. Both terms have (x+4) in common. The first term has (x+4)² and the second term has (x+4)³. The common factor is (x+4)².Factor Out Common Factor: Factor out the common factor from both terms. We can factor (x+4)² out of both terms to get (x+4)²[5 + (x+4)].Simplify Inside Brackets: Simplify the expression inside the brackets. Inside the brackets, we have 5 + (x+4). Simplify this to get 5 + x + 4, which simplifies further to x + 9.Write Final Factored Form: Write the final factored form. The final factored form is (x+4)²(x + 9).

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Factor completely:

5(x+4)^(2)+(x+4)^(3)
Answer:

Factor completely: $\newline$ $5(x+4)^{2}+(x+4)^{3}$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

5(x+4)^{2}+(x+4)^{3}

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms. $\newline$ Both terms have $(x+4)$ in common. The first term has $(x+4)^2$ and the second term has $(x+4)^3$ . The common factor is $(x+4)^2$ .
Factor Out Common Factor: Factor out the common factor from both terms. $\newline$ We can factor $(x+4)^2$ out of both terms to get $(x+4)^2[5 + (x+4)]$ .
Simplify Inside Brackets: Simplify the expression inside the brackets. $\newline$ Inside the brackets, we have $5 + (x+4)$ . Simplify this to get $5 + x + 4$ , which simplifies further to $x + 9$ .
Write Final Factored Form: Write the final factored form. $\newline$ The final factored form is $(x+4)^2(x + 9)$ .