Factor completely: (4x-1)^(2)-(x+10)^(2) Answer:

Recognize as difference of squares: Recognize the expression as a difference of squares. The given expression is in the form of a^2 - b^2, which can be factored into (a + b)(a - b).Identify 'a' and 'b': Identify 'a' and 'b' in the expression. In the expression (4x-1)^(2)-(x+10)^(2), 'a' is (4x-1) and 'b' is (x+10).Apply formula: Apply the difference of squares formula. Using the formula (a + b)(a - b), we get ((4x-1) + (x+10))((4x-1) - (x+10)).Simplify expressions: Simplify the expressions inside the parentheses. Simplify (4x-1) + (x+10) to get 5x + 9. Simplify (4x-1) - (x+10) to get 3x - 11.Write factored form: Write the factored form of the expression. The factored form is (5x + 9)(3x - 11).

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Factor completely:

(4x-1)^(2)-(x+10)^(2)
Answer:

Factor completely: $\newline$ $(4 x-1)^{2}-(x+10)^{2}$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

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Q. Factor completely:

\newline

(4 x-1)^{2}-(x+10)^{2}

\newline

Answer:

Recognize as difference of squares: Recognize the expression as a difference of squares. The given expression is in the form of $a^2 - b^2$ , which can be factored into $(a + b)(a - b)$ .
Identify 'a' and 'b': Identify 'a' and 'b' in the expression. $\newline$ In the expression $(4x-1)^{2}-(x+10)^{2}$ , 'a' is $(4x-1)$ and 'b' is $(x+10)$ .
Apply formula: Apply the difference of squares formula. $\newline$ Using the formula $(a + b)(a - b)$ , we get $((4x-1) + (x+10))((4x-1) - (x+10))$ .
Simplify expressions: Simplify the expressions inside the parentheses. $\newline$ Simplify $(4x-1) + (x+10)$ to get $5x + 9$ . $\newline$ Simplify $(4x-1) - (x+10)$ to get $3x - 11$ .
Write factored form: Write the factored form of the expression. $\newline$ The factored form is $(5x + 9)(3x - 11)$ .