Factor completely: (4x+1)^(2)-(6x+5)^(2) Answer:

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Factor completely:  (4x+1)^(2)-(6x+5)^(2) Answer:

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Recognize: Recognize the expression as a difference of squares. The given expression is in the form of a^2 - b^2, which can be factored into (a + b)(a - b). Here, a = (4x + 1) and b = (6x + 5).Apply formula: Apply the difference of squares formula. Using the formula (a + b)(a - b), we substitute a and b with (4x + 1) and (6x + 5) respectively. Factored form: ((4x + 1) + (6x + 5))((4x + 1) - (6x + 5))Simplify binomials: Simplify each binomial. First binomial: (4x + 1) + (6x + 5) = 4x + 1 + 6x + 5 = 10x + 6 Second binomial: (4x + 1) - (6x + 5) = 4x + 1 - 6x - 5 = -2x - 4Factor common factors: Factor out common factors in the simplified binomials. The first binomial 10x + 6 can be factored further by taking out the common factor 2. First binomial factored: 2(5x + 3) The second binomial -2x - 4 can be factored further by taking out the common factor -2. Second binomial factored: -2(x + 2)Write final form: Write the final factored expression. The factored form of the original expression is the product of the factored binomials. Final factored form: 2(5x + 3)(-2)(x + 2)Simplify final form: Simplify the final factored expression by combining the constants. Combine the constants 2 and -2 from the factored form. Final simplified factored form: -4(5x + 3)(x + 2)

Factor completely: $\newline$ $(4 x+1)^{2}-(6 x+5)^{2}$ $\newline$ Answer:

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Factor completely:\newline(4x+1)2−(6x+5)2 (4 x+1)^{2}-(6 x+5)^{2} (4x+1)2−(6x+5)2\newlineAnswer:

Factor completely: $\newline$ $(4 x+1)^{2}-(6 x+5)^{2}$ $\newline$ Answer: