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Factor completely.

3x^(2)-5x-2
Answer:

Factor completely.\newline3x25x2 3 x^{2}-5 x-2 \newlineAnswer:

Full solution

Q. Factor completely.\newline3x25x2 3 x^{2}-5 x-2 \newlineAnswer:
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3x25x23x^2 - 5x - 2. Compare 3x25x23x^2 - 5x - 2 with ax2+bx+cax^2 + bx + c. a=3a = 3 bb00 bb11
  2. Find product and sum: Find two numbers whose product is aca*c (32=63*-2 = -6) and whose sum is bb (5-5).\newlineWe need to find two numbers that multiply to 6-6 and add up to 5-5.\newlineThe numbers 6-6 and 11 satisfy these conditions because:\newline61=6-6 * 1 = -6 (product)\newline6+1=5-6 + 1 = -5 (sum)
  3. Rewrite middle term: Rewrite the middle term 5x-5x using the two numbers found in Step 22.\newline3x25x23x^2 - 5x - 2 becomes 3x26x+x23x^2 - 6x + x - 2.
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms: (3x26x)+(x2)(3x^2 - 6x) + (x - 2).\newlineFactor out the common factors from each group.\newlineFrom the first group, factor out 3x3x: 3x(x2)3x(x - 2).\newlineFrom the second group, factor out 11: 1(x2)1(x - 2).\newlineNow we have: 3x(x2)+1(x2)3x(x - 2) + 1(x - 2).
  5. Factor out common factor: Factor out the common binomial factor (x2)(x - 2).\newlineThe factored form is (3x+1)(x2)(3x + 1)(x - 2).