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Factor completely.

3x^(2)+2x-5
Answer:

Factor completely.\newline3x2+2x5 3 x^{2}+2 x-5 \newlineAnswer:

Full solution

Q. Factor completely.\newline3x2+2x5 3 x^{2}+2 x-5 \newlineAnswer:
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is 3x2+2x53x^2 + 2x - 5.\newlineHere, a=3a = 3, b=2b = 2, and c=5c = -5.
  2. Check Factorability: Determine if the quadratic expression can be factored using simple factoring techniques.\newlineSince ac=(3)(5)=15ac = (3)(-5) = -15, we need to find two numbers that multiply to 15-15 and add up to the middle coefficient, b=2b = 2.
  3. Find Suitable Numbers: Find two numbers that meet the criteria.\newlineThe numbers 55 and 3-3 multiply to 15-15 and add up to 22.\newline5×3=155 \times -3 = -15\newline5+(3)=25 + (-3) = 2
  4. Rewrite Middle Term: Write the middle term as a sum of two terms using the numbers found.\newlineThe expression 3x2+2x53x^2 + 2x - 5 can be rewritten as 3x2+5x3x53x^2 + 5x - 3x - 5.
  5. Factor by Grouping: Factor by grouping.\newlineGroup the terms as (3x2+5x)+(3x5)(3x^2 + 5x) + (-3x - 5).\newlineFactor out the greatest common factor from each group.\newlineThe first group has a common factor of xx, and the second group has a common factor of 1-1.\newlineThis gives us x(3x+5)1(3x+5)x(3x + 5) - 1(3x + 5).
  6. Factor Common Binomial: Factor out the common binomial factor.\newlineThe common binomial factor is (3x+5)(3x + 5).\newlineThe factored form is (x1)(3x+5)(x - 1)(3x + 5).