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Factor completely.

3x^(2)+10 x+3
Answer:

Factor completely.\newline3x2+10x+3 3 x^{2}+10 x+3 \newlineAnswer:

Full solution

Q. Factor completely.\newline3x2+10x+3 3 x^{2}+10 x+3 \newlineAnswer:
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3x2+10x+33x^2 + 10x + 3. Compare 3x2+10x+33x^2 + 10x + 3 with ax2+bx+cax^2 + bx + c. a=3a = 3 bb00 bb11
  2. Find product and sum: Find two numbers whose product is aca*c (33=93*3 = 9) and whose sum is bb (1010).\newlineWe need to find two numbers that multiply to 99 and add up to 1010.\newlineThe numbers 11 and 99 satisfy these conditions because:\newline19=91 * 9 = 9\newline1+9=101 + 9 = 10
  3. Rewrite middle term: Rewrite the middle term 10x10x using the two numbers found in Step 22.3x2+10x+33x^2 + 10x + 3 can be rewritten as:3x2+1x+9x+33x^2 + 1x + 9x + 3
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms into two pairs:\newline(3x2+1x)+(9x+3)(3x^2 + 1x) + (9x + 3)\newlineFactor out the greatest common factor from each pair:\newlinex(3x+1)+3(3x+1)x(3x + 1) + 3(3x + 1)
  5. Factor out common binomial: Factor out the common binomial factor.\newlineBoth groups contain the common binomial factor (3x+1)(3x + 1), so factor this out:\newline(3x+1)(x+3)(3x + 1)(x + 3)