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Factor completely: (2x+3)(2x-9)+(2x+7)(2x-9) Answer:

Factor completely:\newline(2x+3)(2x−9)+(2x+7)(2x−9) (2 x+3)(2 x-9)+(2 x+7)(2 x-9) \newlineAnswer:

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Full solution

Q. Factor completely:\newline(2x+3)(2x−9)+(2x+7)(2x−9) (2 x+3)(2 x-9)+(2 x+7)(2 x-9) \newlineAnswer:
  1. Recognize common factor: Recognize the common factor in both terms.\newlineThe common factor is (2x−9)(2x-9), which appears in both terms of the expression.
  2. Factor out common factor: Factor out the common factor (2x−9)(2x-9).(2x+3)(2x−9)+(2x+7)(2x−9)=(2x−9)((2x+3)+(2x+7))(2x+3)(2x-9) + (2x+7)(2x-9) = (2x-9)((2x+3) + (2x+7))
  3. Simplify inside parentheses: Simplify the expression inside the parentheses.\newline(2x+3)+(2x+7)(2x+3) + (2x+7)\newline= 2x+3+2x+72x + 3 + 2x + 7\newline= 4x+104x + 10
  4. Write final factored form: Write the final factored form. (2x−9)(4x+10) (2x-9)(4x+10) This is the completely factored form of the given expression.

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