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Factor completely.

2x^(2)+x-3
Answer:

Factor completely.\newline2x2+x3 2 x^{2}+x-3 \newlineAnswer:

Full solution

Q. Factor completely.\newline2x2+x3 2 x^{2}+x-3 \newlineAnswer:
  1. Identify Coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is 2x2+x32x^2 + x - 3.\newlineHere, a=2a = 2, b=1b = 1, and c=3c = -3.
  2. Find Multiplying Numbers: Find two numbers that multiply to aca*c (which is 2(3)=62*(-3) = -6) and add up to bb (which is 11).\newlineWe need to find two numbers that multiply to 6-6 and add up to 11.\newlineThe numbers 2-2 and 33 satisfy these conditions because 23=6-2 * 3 = -6 and 2+3=1-2 + 3 = 1.
  3. Rewrite Middle Term: Rewrite the middle term using the two numbers found.\newlineThe expression 2x2+x32x^2 + x - 3 can be rewritten as 2x22x+3x32x^2 - 2x + 3x - 3 by splitting the middle term.
  4. Factor by Grouping: Factor by grouping.\newlineGroup the terms as follows: 2x22x2x^2 - 2x + 3x33x - 3.\newlineFactor out the common factors from each group.\newlineFrom the first group, factor out 2x2x: 2x(x1)2x(x - 1).\newlineFrom the second group, factor out 33: 3(x1)3(x - 1).
  5. Factor Common Binomial: Factor out the common binomial factor.\newlineThe expression now looks like 2x(x1)+3(x1)2x(x - 1) + 3(x - 1).\newlineThe common binomial factor is (x1)(x - 1).\newlineFactor this out to get (x1)(2x+3)(x - 1)(2x + 3).