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Factor completely.

2x^(2)-3x-2
Answer:

Factor completely.\newline2x23x2 2 x^{2}-3 x-2 \newlineAnswer:

Full solution

Q. Factor completely.\newline2x23x2 2 x^{2}-3 x-2 \newlineAnswer:
  1. Identify coefficients: Identify the coefficients of the quadratic expression.\newlineThe quadratic expression is 2x23x22x^2 - 3x - 2.\newlineHere, a=2a = 2 (coefficient of x2x^2), b=3b = -3 (coefficient of xx), and c=2c = -2 (constant term).
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 2(2)=42*(-2) = -4) and add up to bb (which is 3-3).\newlineWe need to find two numbers that multiply to 4-4 and add to 3-3.\newlineThe numbers 4-4 and 11 satisfy these conditions because 4×1=4-4 \times 1 = -4 and 4+1=3-4 + 1 = -3.
  3. Rewrite middle term: Rewrite the middle term 3x-3x using the two numbers found in the previous step.\newlineWe can express 3x-3x as 4x+x-4x + x.\newlineSo, the expression 2x23x22x^2 - 3x - 2 can be rewritten as 2x24x+x22x^2 - 4x + x - 2.
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms into two pairs: 2x24x2x^2 - 4x and x2x - 2.\newlineFactor out the common factors from each pair.\newlineFrom the first pair, we can factor out 2x2x, giving us 2x(x2)2x(x - 2).\newlineFrom the second pair, we can factor out 11, giving us 1(x2)1(x - 2).\newlineNow we have 2x(x2)+1(x2)2x(x - 2) + 1(x - 2).
  5. Factor out common factor: Factor out the common binomial factor (x2)(x - 2). The expression can now be written as (x2)(2x+1)(x - 2)(2x + 1).