Factor completely: 25x^(2)(x^(2)+3)-9(x^(2)+3) Answer:

Identify Common Factor: Identify the common factor in both terms. Both terms have (x^(2) + 3) as a common factor.Factor Out Common Factor: Factor out the common factor (x^(2) + 3). The expression becomes (x^(2) + 3)(25x^(2) - 9).Look for Further Factoring: Look for further factoring possibilities. The second term (25x^(2) - 9) is a difference of squares, which can be factored further.Factor Difference of Squares: Factor the difference of squares. The difference of squares 25x^(2) - 9 can be factored into (5x + 3)(5x - 3).Write Completely Factored Expression: Write the completely factored expression. The completely factored expression is (x^(2) + 3)(5x + 3)(5x - 3).

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Factor completely:

25x^(2)(x^(2)+3)-9(x^(2)+3)
Answer:

Factor completely: $\newline$ $25 x^{2}\left(x^{2}+3\right)-9\left(x^{2}+3\right)$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

25 x^{2}\left(x^{2}+3\right)-9\left(x^{2}+3\right)

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms. $\newline$ Both terms have $(x^{2} + 3)$ as a common factor.
Factor Out Common Factor: Factor out the common factor $(x^{2} + 3)$ . The expression becomes $(x^{2} + 3)(25x^{2} - 9)$ .
Look for Further Factoring: Look for further factoring possibilities. The second term $25x^{2} - 9$ is a difference of squares, which can be factored further.
Factor Difference of Squares: Factor the difference of squares. $\newline$ The difference of squares $25x^{2} - 9$ can be factored into $(5x + 3)(5x - 3)$ .
Write Completely Factored Expression: Write the completely factored expression. $\newline$ The completely factored expression is $(x^{2} + 3)(5x + 3)(5x - 3)$ .