Factor completely: 2(4x-3)^(4)+(4x-3)^(5) Answer:

Identify common factor: Identify the common factor in both terms. The common factor in both terms is (4x-3)^(4) since it is present in both terms of the expression.Factor out: Factor out the common factor from the expression. We can factor (4x-3)^(4) out of both terms to get (4x-3)^(4)(2 + (4x-3)).Simplify expression: Simplify the expression inside the parentheses. Simplifying the expression inside the parentheses gives us (4x-3)^(4)(2 + 4x - 3).Combine like terms: Combine like terms inside the parentheses. Combining like terms 2 and -3 gives us (4x-3)^(4)(4x - 1).Write final form: Write down the final factored form. The completely factored form of the expression is (4x-3)^(4)(4x - 1).

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Factor completely:

2(4x-3)^(4)+(4x-3)^(5)
Answer:

Factor completely: $\newline$ $2(4 x-3)^{4}+(4 x-3)^{5}$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

2(4 x-3)^{4}+(4 x-3)^{5}

\newline

Answer:

Identify common factor: Identify the common factor in both terms. $\newline$ The common factor in both terms is $(4x-3)^{4}$ since it is present in both terms of the expression.
Factor out: Factor out the common factor from the expression. $\newline$ We can factor $(4x-3)^{4}$ out of both terms to get $(4x-3)^{4}(2 + (4x-3))$ .
Simplify expression: Simplify the expression inside the parentheses. $\newline$ Simplifying the expression inside the parentheses gives us $(4x-3)^{4}(2 + 4x - 3)$ .
Combine like terms: Combine like terms inside the parentheses. $\newline$ Combining like terms $2$ and $-3$ gives us $(4x-3)^{4}(4x - 1)$ .
Write final form: Write down the final factored form. $\newline$ The completely factored form of the expression is $(4x-3)^{4}(4x - 1)$ .