Factor completely: 16x^(2)(x^(2)-5)-9(x^(2)-5) Answer:

Identify common factor: Identify the common factor in both terms. The common factor in both terms is (x^(2) - 5).Factor out common factor: Factor out the common factor from both terms. The expression can be written as (x^(2) - 5)(16x^(2) - 9).Recognize perfect squares: Recognize that both terms in the parentheses are perfect squares. 16x^(2) is the square of 4x, and 9 is the square of 3.Factor difference of squares: Factor the difference of squares in the second term. The expression (16x^(2) - 9) can be factored as (4x + 3)(4x - 3).Write final factored form: Write the final factored form of the original expression. The completely factored form is (x^(2) - 5)(4x + 3)(4x - 3).

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Factor completely:

16x^(2)(x^(2)-5)-9(x^(2)-5)
Answer:

Factor completely: $\newline$ $16 x^{2}\left(x^{2}-5\right)-9\left(x^{2}-5\right)$ $\newline$ Answer:

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Math Problems

Grade 6

Factor numerical expressions using the distributive property

Full solution

Q. Factor completely:

\newline

16 x^{2}\left(x^{2}-5\right)-9\left(x^{2}-5\right)

\newline

Answer:

Identify common factor: Identify the common factor in both terms. $\newline$ The common factor in both terms is $(x^{2} - 5)$ .
Factor out common factor: Factor out the common factor from both terms. $\newline$ The expression can be written as $(x^{2} - 5)(16x^{2} - 9)$ .
Recognize perfect squares: Recognize that both terms in the parentheses are perfect squares. $16x^{2}$ is the square of $4x$ , and $9$ is the square of $3$ .
Factor difference of squares: Factor the difference of squares in the second term. $\newline$ The expression $(16x^{2} - 9)$ can be factored as $(4x + 3)(4x - 3)$ .
Write final factored form: Write the final factored form of the original expression. $\newline$ The completely factored form is $(x^{2} - 5)(4x + 3)(4x - 3)$ .