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Factor completely. 162p2242162p^2-242

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Q. Factor completely. 162p2242162p^2-242
  1. Identify GCF: Identify the greatest common factor (GCF) of the terms 162p2162p^2 and 242242. Both numbers are even, so 22 is a factor. We can check for higher factors that are common to both numbers.
  2. Divide by 22: Divide both 162162 and 242242 by 22 to see if there is a larger common factor. 162÷2=81162 \div 2 = 81 and 242÷2=121242 \div 2 = 121. Both 8181 and 121121 are perfect squares (929^2 and 11211^2, respectively), so the GCF is not just 22. We can try to factor out a larger number.
  3. Check for 33: Since 8181 and 121121 are both multiples of 33, we can divide them by 33 to see if 33 is a common factor. 81÷3=2781 \div 3 = 27 and 121121 is not divisible by 33. Therefore, 33 is not a common factor for both terms. We should go back and check for the largest common factor that includes 22.
  4. Factor out 22: We know that 8181 is 343^4 and 121121 is 11211^2. Since 33 is not a factor of 121121, we can conclude that the GCF is 22. Now we can factor out 22 from both terms.
  5. Factor inside parentheses: Factoring out the GCF of 22, we get 2(81p2121)2(81p^2 - 121). We can now look at each term inside the parentheses to see if they can be factored further.
  6. Apply difference of squares: Inside the parentheses, we have a difference of squares since 81p281p^2 is (9p)2(9p)^2 and 121121 is 11211^2. We can factor the difference of squares as (a2b2)=(a+b)(ab)(a^2 - b^2) = (a + b)(a - b).
  7. Verify factoring: Apply the difference of squares factoring to get 2((9p+11)(9p11))2((9p + 11)(9p - 11)).
  8. Verify factoring: Apply the difference of squares factoring to get 2((9p+11)(9p11))2((9p + 11)(9p - 11)).Check the factoring for any possible errors. 2×(9p+11)×(9p11)2 \times (9p + 11) \times (9p - 11) should expand back to the original expression 162p2242162p^2 - 242. Let's expand it to verify: 2×(81p299p+99p121)2 \times (81p^2 - 99p + 99p - 121) simplifies to 2×(81p2121)2 \times (81p^2 - 121), which is 162p2242162p^2 - 242. The factoring is correct.

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