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Factor completely:

1+r^(9)
Answer:

Factor completely:\newline1+r9 1+r^{9} \newlineAnswer:

Full solution

Q. Factor completely:\newline1+r9 1+r^{9} \newlineAnswer:
  1. Identify Expression Type: Identify the type of expression and the possible factoring technique.\newlineThe expression 1+r91 + r^9 is a sum of two terms. One of the terms is a perfect power of rr. We can consider if it's possible to apply a sum of cubes or a sum of higher powers factoring technique.
  2. Recognize Perfect Cube: Recognize that r9r^9 is a perfect cube, as r9=(r3)3r^9 = (r^3)^3. The expression can be rewritten as 13+(r3)31^3 + (r^3)^3, which resembles the sum of cubes formula a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2).
  3. Apply Sum of Cubes Formula: Apply the sum of cubes formula to factor the expression.\newlineUsing the formula, we have:\newline1+r9=13+(r3)3=(1+r3)(121r3+r6)1 + r^9 = 1^3 + (r^3)^3 = (1 + r^3)(1^2 - 1\cdot r^3 + r^6).
  4. Simplify Factored Expression: Simplify the factored expression.\newlineSimplifying the second factor, we get:\newline(1+r3)(1r3+r6)(1 + r^3)(1 - r^3 + r^6).
  5. Check Further Factoring: Check for further factoring possibilities. The second factor 1r3+r61 - r^3 + r^6 does not factor further using standard algebraic identities or methods for polynomials. Therefore, the expression is fully factored.