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Factor completely:

1-d^(6)
Answer:

Factor completely:\newline1d6 1-d^{6} \newlineAnswer:

Full solution

Q. Factor completely:\newline1d6 1-d^{6} \newlineAnswer:
  1. Recognize Difference of Squares: Step Title: Recognize the Difference of Squares\newlineConcise Step Description: Identify that the expression is a difference of squares, which can be factored into the product of a sum and difference.\newlineStep Calculation: Recognize that 1d61 - d^6 can be written as 12(d3)21^2 - (d^3)^2.
  2. Apply Squares Formula: Step Title: Apply the Difference of Squares Formula\newlineConcise Step Description: Use the difference of squares formula a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b) to factor the expression.\newlineStep Calculation: Factor 12(d3)21^2 - (d^3)^2 into (1+d3)(1d3)(1 + d^3)(1 - d^3).
  3. Factor Difference of Squares: Step Title: Factor the Resulting Difference of Squares\newlineConcise Step Description: Recognize that 1d31 - d^3 is also a difference of cubes and can be further factored.\newlineStep Calculation: Factor 1d31 - d^3 using the difference of cubes formula a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2) to get (1d)(1+d+d2)(1 - d)(1 + d + d^2).
  4. Combine Factored Forms: Step Title: Combine the Factored Forms\newlineConcise Step Description: Combine the factored forms from the previous steps to write the completely factored expression.\newlineStep Calculation: The completely factored form is (1+d3)(1d)(1+d+d2)(1 + d^3)(1 - d)(1 + d + d^2).