Factor completely. 1-36x^(2) Answer:

Identify Form: Identify the form of the expression. The expression 1 - 36x^2 is a difference of squares because it can be written as a^2 - b^2, where a = 1 and b = 6x.Write Expression: Write the expression as a difference of squares. 1 - 36x^2 = (1)^2 - (6x)^2Apply Formula: Apply the difference of squares formula. The difference of squares formula is a^2 - b^2 = (a + b)(a - b). Here, a = 1 and b = 6x. So, 1 - 36x^2 = (1 + 6x)(1 - 6x)Check Factored Form: Check the factored form by expanding. (1 + 6x)(1 - 6x) = 1 - 6x + 6x - 36x^2 = 1 - 36x^2 The expanded form matches the original expression, so there is no math error.

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Algebra 1

Factor polynomials

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Q. Factor completely.

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1-36 x^{2}

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Answer:

Identify Form: Identify the form of the expression. $\newline$ The expression $1 - 36x^2$ is a difference of squares because it can be written as $a^2 - b^2$ , where $a = 1$ and $b = 6x$ .
Write Expression: Write the expression as a difference of squares. $\newline$ $1 - 36x^2 = (1)^2 - (6x)^2$
Apply Formula: Apply the difference of squares formula. $\newline$ The difference of squares formula is $a^2 - b^2 = (a + b)(a - b)$ . Here, $a = 1$ and $b = 6x$ . $\newline$ So, $1 - 36x^2 = (1 + 6x)(1 - 6x)$
Check Factored Form: Check the factored form by expanding. $\newline$ $(1 + 6x)(1 - 6x) = 1 - 6x + 6x - 36x^2 = 1 - 36x^2$ $\newline$ The expanded form matches the original expression, so there is no math error.