Factor. 9yz - 9y + 8z - 8 ______

Group Terms: Group the terms that have common factors. We can group the terms as follows: (9yz - 9y) + (8z - 8).Factor Common Factors: Factor out the common factors from each group. From the first group (9yz - 9y), we can factor out 9y, giving us 9y(z - 1). From the second group (8z - 8), we can factor out 8, giving us 8(z - 1).Rewrite Expression: Rewrite the expression using the factored groups. The expression now looks like this: 9y(z - 1) + 8(z - 1).Factor Binomial Factor: Factor out the common binomial factor (z - 1). Both terms have a (z - 1) factor, so we can factor that out to get (z - 1)(9y + 8).

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Q. Factor.

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9yz - 9y + 8z - 8

Group Terms: Group the terms that have common factors. $\newline$ We can group the terms as follows: $9yz - 9y$ + $8z - 8$ .
Factor Common Factors: Factor out the common factors from each group. $\newline$ From the first group $9yz - 9y$ , we can factor out $9y$ , giving us $9y(z - 1)$ . $\newline$ From the second group $8z - 8$ , we can factor out $8$ , giving us $8(z - 1)$ .
Rewrite Expression: Rewrite the expression using the factored groups. $\newline$ The expression now looks like this: $9y(z - 1) + 8(z - 1)$ .
Factor Binomial Factor: Factor out the common binomial factor $(z - 1)$ . Both terms have a $(z - 1)$ factor, so we can factor that out to get $(z - 1)(9y + 8)$ .