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Factor.\newline9w2+11w+29w^2 + 11w + 2

Full solution

Q. Factor.\newline9w2+11w+29w^2 + 11w + 2
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 9w2+11w+29w^2 + 11w + 2 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=9a = 9, b=11b = 11, c=2c = 2
  2. Find two numbers: Find two numbers that multiply to aca*c (92=189*2 = 18) and add up to bb (1111).\newlineThe numbers that satisfy these conditions are 99 and 22 because 92=189*2 = 18 and 9+2=119+2 = 11.
  3. Rewrite middle term: Rewrite the middle term 11w11w using the two numbers found in the previous step.\newline9w2+11w+29w^2 + 11w + 2 can be rewritten as 9w2+9w+2w+29w^2 + 9w + 2w + 2.
  4. Group terms: Group the terms into two pairs: 9w2+9w9w^2 + 9w and 2w+22w + 2.
  5. Factor out common factor: Factor out the greatest common factor from each pair.\newlineFrom the first pair 9w2+9w9w^2 + 9w, factor out 9w9w to get 9w(w+1)9w(w + 1).\newlineFrom the second pair 2w+22w + 2, factor out 22 to get 2(w+1)2(w + 1).
  6. Write factored form: Notice that both groups now have a common factor of (w+1)(w + 1).\newlineWrite the expression as the product of this common factor and the factors found in the previous step.\newlineThe factored form is (9w+2)(w+1)(9w + 2)(w + 1).