Factor. 9g^3 + 9g^2 - 10g - 10 ______

Group Terms: Group the terms to find common factors. We can group the terms as follows: (9g^3 + 9g^2) and (-10g - 10).Factor Common Factors: Factor out the greatest common factor from each group. From the first group (9g^3 + 9g^2), we can factor out 9g^2, which gives us 9g^2(g + 1). From the second group (-10g - 10), we can factor out -10, which gives us -10(g + 1).Write Factored Expression: Write the expression with the factored groups. Now we have 9g^2(g + 1) - 10(g + 1).Factor Common Binomial: Factor out the common binomial factor. We notice that (g + 1) is a common factor in both terms, so we factor it out to get (g + 1)(9g^2 - 10).Check Quadratic Factor: Check if the quadratic factor can be factored further. The quadratic factor 9g^2 - 10 does not factor nicely with integer coefficients, so it is already in its simplest form.

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Factor by grouping

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Q. Factor.

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9g^3 + 9g^2 - 10g - 10

Group Terms: Group the terms to find common factors. $\newline$ We can group the terms as follows: $(9g^3 + 9g^2)$ and $(-10g - 10)$ .
Factor Common Factors: Factor out the greatest common factor from each group. $\newline$ From the first group $9g^3 + 9g^2$ , we can factor out $9g^2$ , which gives us $9g^2(g + 1)$ . $\newline$ From the second group $-10g - 10$ , we can factor out $-10$ , which gives us $-10(g + 1)$ .
Write Factored Expression: Write the expression with the factored groups. $\newline$ Now we have $9g^2(g + 1) - 10(g + 1)$ .
Factor Common Binomial: Factor out the common binomial factor. $\newline$ We notice that $(g + 1)$ is a common factor in both terms, so we factor it out to get $(g + 1)(9g^2 - 10)$ .
Check Quadratic Factor: Check if the quadratic factor can be factored further. $\newline$ The quadratic factor $9g^2 - 10$ does not factor nicely with integer coefficients, so it is already in its simplest form.