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Factor.\newline7y2+9y+27y^2 + 9y + 2

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Q. Factor.\newline7y2+9y+27y^2 + 9y + 2
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 7y2+9y+27y^2 + 9y + 2. Compare 7y2+9y+27y^2 + 9y + 2 with the standard form ay2+by+cay^2 + by + c. a=7a = 7 bb00 bb11
  2. Find numbers for multiplication: Find two numbers that multiply to aca*c (which is 72=147*2=14) and add up to bb (which is 99).\newlineWe need to find two numbers that satisfy these conditions.\newlineAfter checking possible pairs that multiply to 1414 (such as 11 and 1414, 22 and 77), we find that the pair 11 and 1414 does not add up to 99, but the pair 22 and 77 does.\newlineSo, the two numbers are 22 and 77.
  3. Rewrite middle term: Rewrite the middle term 9y9y using the two numbers found in Step 22.\newlineWe can express 9y9y as 7y+2y7y + 2y.\newlineSo, the expression 7y2+9y+27y^2 + 9y + 2 can be rewritten as 7y2+7y+2y+27y^2 + 7y + 2y + 2.
  4. Factor by grouping: Factor by grouping.\newlineWe group the terms as follows: 7y2+7y7y^2 + 7y + 2y+22y + 2.\newlineNow, factor out the greatest common factor from each group.\newlineFrom the first group, we can factor out 7y7y, giving us 7y(y+1)7y(y + 1).\newlineFrom the second group, we can factor out 22, giving us 2(y+1)2(y + 1).
  5. Write factored form: Write the factored form of the expression.\newlineSince both groups contain the factor (y+1)(y + 1), we can factor this out.\newlineThe factored form is (7y+2)(y+1)(7y + 2)(y + 1).