Factor. 7st + 7s + 3t + 3 ______

Identify Factors: Identify common factors in pairs of terms. We can group the terms as (7st + 7s) and (3t + 3) to look for common factors in each group.Factor Out Common Factors: Factor out the common factors from each group. From the first group (7st + 7s), we can factor out 7s, giving us 7s(t + 1). From the second group (3t + 3), we can factor out 3, giving us 3(t + 1).Rewrite Expression: Rewrite the expression with the factored groups. The expression now looks like 7s(t + 1) + 3(t + 1).Factor Out Binomial Factor: Factor out the common binomial factor. We can see that (t + 1) is a common factor in both terms, so we factor it out. The factored form is (t + 1)(7s + 3).

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Q. Factor.

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7st + 7s + 3t + 3

Identify Factors: Identify common factors in pairs of terms. $\newline$ We can group the terms as $7st + 7s$ and $3t + 3$ to look for common factors in each group.
Factor Out Common Factors: Factor out the common factors from each group. $\newline$ From the first group $7st + 7s$ , we can factor out $7s$ , giving us $7s(t + 1)$ . $\newline$ From the second group $3t + 3$ , we can factor out $3$ , giving us $3(t + 1)$ .
Rewrite Expression: Rewrite the expression with the factored groups. $\newline$ The expression now looks like $7s(t + 1) + 3(t + 1)$ .
Factor Out Binomial Factor: Factor out the common binomial factor. $\newline$ We can see that $(t + 1)$ is a common factor in both terms, so we factor it out. $\newline$ The factored form is $(t + 1)(7s + 3)$ .