Identify Common Factor: Look for a common factor in all terms.Check if there is a greatest common factor (GCF) that can be factored out from all terms of the polynomial 6u3−8u2−15u+20.The GCF of 6u3, 8u2, 15u, and 20 is 1, so there is no common factor other than 1.
Grouping for Factoring: Group terms to facilitate factoring by grouping.We can group the terms as follows: 6u3−8u2 and −15u+20.Now we will look for common factors within each group.
Factor Out from First Group: Factor out the common factor from the first group.In the first group (6u3−8u2), we can factor out 2u2, which gives us 2u2(3u−4).
Factor Out from Second Group: Factor out the common factor from the second group.In the second group (−15u+20), we can factor out −5, which gives us −5(3u−4).
Write Factored Form: Write the factored form of the polynomial.We now have 2u2(3u−4)−5(3u−4). Notice that (3u−4) is a common factor.We can factor (3u−4) out of both terms, which gives us (3u−4)(2u2−5).
Check Further Factoring: Check for any further factoring possibilities.The terms 2u2 and −5 do not have any common factors, and 2u2−5 cannot be factored further over the integers.Therefore, the factored form of the polynomial is (3u−4)(2u2−5).