Factor. 6j^2 + 24j + 18 ____

Identify Common Factor: First, look for a common factor in all terms. 6j^2 + 24j + 18 can be divided by 6.Divide by Common Factor: Divide each term by 6. 6j^2 ÷ 6 = j^2, 24j ÷ 6 = 4j, 18 ÷ 6 = 3. So, 6j^2 + 24j + 18 = 6(j^2 + 4j + 3).Factor Quadratic Inside: Now, factor the quadratic inside the parentheses. We need two numbers that multiply to 3 and add to 4.Find Correct Numbers: The numbers are 3 and 1 because 3 * 1 = 3 and 3 + 1 = 4. So, j^2 + 4j + 3 can be factored as (j + 3)(j + 1).Write Final Factored Form: Write the final factored form including the 6 we factored out earlier. 6(j^2 + 4j + 3) = 6(j + 3)(j + 1).

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Algebra 2

Factor quadratics

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Q. Factor.

\newline

6j^2 + 24j + 18

Identify Common Factor: First, look for a common factor in all terms. $6j^2 + 24j + 18$ can be divided by $6$ .
Divide by Common Factor: Divide each term by $6$ . $\newline$ $6j^2 \div 6 = j^2$ , $24j \div 6 = 4j$ , $18 \div 6 = 3$ . $\newline$ So, $6j^2 + 24j + 18 = 6(j^2 + 4j + 3)$ .
Factor Quadratic Inside: Now, factor the quadratic inside the parentheses. $\newline$ We need two numbers that multiply to $3$ and add to $4$ .
Find Correct Numbers: The numbers are $3$ and $1$ because $3 \times 1 = 3$ and $3 + 1 = 4$ . So, $j^2 + 4j + 3$ can be factored as $(j + 3)(j + 1)$ .
Write Final Factored Form: Write the final factored form including the $6$ we factored out earlier. $\newline$ $6(j^2 + 4j + 3) = 6(j + 3)(j + 1)$ .